# Exercises So this lesson only had 4 exercises (from what I could see, anyway), but for some reason they start at 16.  At any rate, this lesson was about modules. `math` and `random` were at the focus of the lesson and its exercises.  Problem 16 ---------- _Use a_ `for` _statement to print 10 random numbers._ ### My Code ```text-x-python # Runestone.Academy thinkcspy course # Chapter 5 # Problem 16 import random for i in range(10): prob = random.random() print(i+1, '-', prob) ``` ### Result ![](Exercises/image.png) Result from the first run of this script Problem 17 ---------- _Repeat the above exercise but this time print 10 random numbers between 25 and 35, inclusive._ ### My Code ```text-x-python # Runestone.Academy thinkcspy course # Chapter 5 # Problem 17 import random for i in range(10): prob = random.randrange(25, 36) print(i+1, '-', prob) ``` ### Result ![](Exercises/1_image.png) Result from the first run of this script Problem 18 ---------- _The **Pythagorean Theorem** tells us that the length of the hypotenuse of a right triangle is related to the lengths of the other two sides. Look through the_ `math` _module and see if you can find a function that will compute this relationship for you. Once you find it, write a short program to try it out._ ### My Code ```text-x-python # Runestone.Academy thinkcspy course # Chapter 5 # Problem 18 import math a = float(input('What is the length of the first side of the triangle?')) b = float(input('What is the length of the second side of the triangle?')) c = math.sqrt(a*a + b*b) print('The hypotenuse of this triangle with is', c, '.') ``` ### Result ![](Exercises/2_image.png) The numbers used to get this result were 12 and 12. Problem 19 ---------- _Search on the internet for a way to calculate an approximation for **pi**. There are many that use simple arithmetic. Write a program to compute the approximation and then print that value as well as the value of_ `math.pi` _from the math module._ ### My Code ```text-x-python # Runestone.Academy thinkcspy course # Chapter 5 # Problem 19 import math c = float(input("Today we are going to calculate pi from the dimensions of a circle. What is the circumference of your circle?")) d = float(input("And what is the diameter of your circle?")) zpi = c/d print("The approximate value of pi from the dimensions provided is", zpi) print("The actual (also technically approximate) value of pi is", math.pi) ``` ### Result ![](Exercises/3_image.png) The numbers were 22.2817 for the diameter and 70 for the circumference. The numbers were generated on [this site](https://www.omnicalculator.com/math/circle-measurements).