Add Exercise files

thinkcspy/Chapter-5-Exercises/Exercises.md

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+# Exercises
+So this lesson only had 4 exercises (from what I could see, anyway), but for some reason they start at 16. 
+
+At any rate, this lesson was about modules. `math` and `random` were at the focus of the lesson and its exercises. 
+
+Problem 16
+----------
+
+_Use a_ `for` _statement to print 10 random numbers._
+
+### My Code
+
+```text-x-python
+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 16
+
+import random
+
+for i in range(10):
+    prob = random.random()
+    print(i+1, '-', prob)
+```
+
+### Result
+
+![](Exercises/image.png)
+
+Result from the first run of this script
+
+Problem 17
+----------
+
+_Repeat the above exercise but this time print 10 random numbers between 25 and 35, inclusive._
+
+### My Code
+
+```text-x-python
+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 17
+
+import random
+
+for i in range(10):
+    prob = random.randrange(25, 36)
+    print(i+1, '-', prob)
+```
+
+### Result
+
+![](Exercises/1_image.png)
+
+Result from the first run of this script
+
+Problem 18
+----------
+
+_The **Pythagorean Theorem** tells us that the length of the hypotenuse of a right triangle is related to the lengths of the other two sides. Look through the_ `math` _module and see if you can find a function that will compute this relationship for you. Once you find it, write a short program to try it out._
+
+### My Code
+
+```text-x-python
+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 18
+
+import math
+
+a = float(input('What is the length of the first side of the triangle?'))
+b = float(input('What is the length of the second side of the triangle?'))
+ 
+c = math.sqrt(a*a + b*b)
+
+print('The hypotenuse of this triangle with is', c, '.')
+```
+
+### Result
+
+![](Exercises/2_image.png)
+
+The numbers used to get this result were 12 and 12.
+
+Problem 19
+----------
+
+_Search on the internet for a way to calculate an approximation for **pi**. There are many that use simple arithmetic. Write a program to compute the approximation and then print that value as well as the value of_ `math.pi` _from the math module._
+
+### My Code
+
+```text-x-python
+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 19
+
+import math
+
+c = float(input("Today we are going to calculate pi from the dimensions of a circle. What is the circumference of your circle?"))
+d = float(input("And what is the diameter of your circle?"))
+               
+zpi = c/d
+
+print("The approximate value of pi from the dimensions provided is", zpi)
+print("The actual (also technically approximate) value of pi is", math.pi)
+```
+
+### Result
+
+![](Exercises/3_image.png)
+
+The numbers were 22.2817 for the diameter and 70 for the circumference. The numbers were generated on [this site](https://www.omnicalculator.com/math/circle-measurements).

thinkcspy/Chapter-5-Exercises/Python-files/problem16.py

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+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 16
+
+import random
+
+for i in range(10):
+    prob = random.random()
+    print(i+1, '-', prob)

thinkcspy/Chapter-5-Exercises/Python-files/problem17.py

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+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 17
+
+import random
+
+for i in range(10):
+    prob = random.randrange(25, 36)
+    print(i+1, '-', prob)

thinkcspy/Chapter-5-Exercises/Python-files/problem18.py

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+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 16
+
+import math
+
+a = float(input('What is the length of the first side of the triangle?'))
+b = float(input('What is the length of the second side of the triangle?'))
+ 
+c = math.sqrt(a*a + b*b)
+
+print('The hypotenuse of this triangle with is', c, '.')

thinkcspy/Chapter-5-Exercises/Python-files/problem19.py

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+# Runestone.Academy thinkcspy course
+# Chapter 5
+# Problem 19
+
+import math
+
+c = float(input("Today we are going to calculate pi from the dimensions of a circle. What is the circumference of your circle?"))
+d = float(input("And what is the diameter of your circle?"))
+               
+zpi = c/d
+
+print("The approximate value of pi from the dimensions provided is", zpi)
+print("The actual (also technically approximate) value of pi is", math.pi)